JEE Advanced Previous Year Questions of Chemistry with Solutions are available at eSaral. (A,C), If $\mathrm{T}_{2}>\mathrm{T}_{1},$ the correct statement(s) is (are), (Assume $\Delta \mathrm{H}^{\theta}$ and $\Delta \mathrm{S}^{\theta}$ are independent of temperature and ratio of $\ln \mathrm{K}$ at $\mathrm{T}_{1}$ to $\ln \mathrm{K}$ at $\mathrm{T}_{2}$ is greater than $\mathrm{T}_{2 / \mathrm{T}_{\mathrm{T}}}$. Get detailed Class 11th &12th Physics Notes to prepare for Boards as well as competitive exams like IIT JEE, NEET etc. $\mathrm{C}_{\mathrm{p}}$ and $\mathrm{C}_{\mathrm{v}}$ are specific heats at constant pressure and constant volume respectively. 2 The question bank consists of Answer key and solutions to all the problems … For a reaction, $\mathbf{A} \square \mathbf{P}$, the plots of [A] and [P] with time at temperatures $\mathrm{T}_{1}$ and $\mathrm{T}_{2}$ are given below. (A,D), (C) $\mathrm{W}_{\text {isothermal }}>\mathrm{W}_{\text {adiabatic }}$, (D) $\Delta \mathrm{U}_{\text {isothemal }}>\Delta \mathrm{U}_{\text {adibaic }}$, Q. The succeeding operations that enable this transformation of states are 1,2,3 Also, JEE Previous Year Question Papers with solutions, online test series, model papers, NCERT Books, extra preparation books are present to help you prepare for JEE. (1) (a) 195 K (b) –2.7 kJ JEE Advanced Previous Year Questions of Physics with Solutions are available at eSaral. (D) Cooling, heating, heating, cooling A diatomic ideal gas is used in a carnot engine as the working substance. Download JEE Mains Physics Practice Sample Paper with Answer and complete Solution. 2018 (4), (1) 1076 R            (2) 1904 R           (3) Zero             (4) 276 R, Q. The amount of work required to cool the vessel is:-, A container with insulating walls is divided into two equal parts by a partition fitted with a valve. A fixed mass ‘m’ of a gas is subjected to transformation of states from K to L to M to N and back to K as shown in the figure. Which of the following choice(s) is (are) correct ? Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Wave on String – JEE Main Previous Year Questions with Solutions, JEE Main Previous Year Questions Topicwise. Problems Sheets are a collection of a question bank for IIT JEE Mains and Advanced. Q. For this expansion, Besides this, eSaral also offers NCERT Solutions, Previous year questions for JEE Main and Advance, Practice questions, Test Series for JEE Main, JEE Advanced and NEET, Important questions of Physics, Chemistry, Math, and Biology and many more. [AIEEE-2009] (A) With increase in temperature, the value of K for exothermic reaction decreases because the entropy change of the system is positive (b) isothermal work. All the topics of Heat and Thermodynamics have been prepared in accordance with the elite exams like IIT JEE (Main and Advanced). These questions are prepared by experts who have spent years in the field of teaching. waste app in the world because not giving complete answers. Students who solve the previous year question papers of JEE Main/Advanced understand better the trend of questions and topics asked in past … JEE Advanced 2020 Paper 2 Analysis. (A) Internal energy For a reaction, $\mathbf{A} \square \mathbf{P}$, the plots of [A] and [P] with time at temperatures $\mathrm{T}_{1}$ and $\mathrm{T}_{2}$ are given below. [JEE 2013] $\Delta \mathrm{U}=\mathrm{nC}_{\mathrm{v}} \Delta \mathrm{T} \Rightarrow \Delta \mathrm{T}<0$ (1) 600 K Some of the valuable JEE Main Physics preparation tips include management of time during preparation and the exam, the important chapters, and topics to focus on as per weightage gave, practising with the previous year question paper, sample papers and taking mock tests on a regular base to name few. Download eSaral app for free study material and video tutorials. By solving JEE Main Sep 2020 chapterwise questions with solutions will help you to score more in your IIT JEE examination. This course is concerned with the previous year subjective questions of thermodynamics asked in IIT JEE. The final state Z can be reached by either of the two paths shown in the figure. Thermo dynamics for physics and chemistry is almost same. One mole of an ideal gas at 300 K in thermal contact with surroundings expands isothermally from 1.0 L to 2.0 L against a constant pressure of 3.0 atm. (A) K to L and L to M Atomic Structure Revision Video – Class 11, JEE, NEET. The final internal pressure, volume and absolute temperature of the gas are $P_{2}$, $\mathrm{V}_{2}$ and $\mathrm{T}_{2}$, respectively. SHOW SOLUTION [jEE-Mains-2016] Download India's Best Exam Preparation App. SHOW SOLUTION Assuming the gas to be ideal the work done on the gas in taking it from A to B is :- (2). SHOW SOLUTION LATEST POSTS: [PDF] Download Mathematics JEE Main Question bank with solutions Part1 December 7, 2020 [Videos] Rapid crash course for JEE Main 2020 November 16, 2020 [Videos] Complete Etoos Videos series for free MPC November 11, 2020 [PDF] Download S.B.Mathur solved problems in Physics November 4, 2020 [PDF] Read JH Sir Physical … [jEE-Mains-2013] ), (A) $\Delta \mathrm{H}^{\theta}<0, \Delta \mathrm{S}^{\theta}<0$, (B) $\Delta \mathrm{G}^{\theta}<0, \Delta \mathrm{H}^{\theta}>0$, (C) $\Delta \mathrm{G}^{\theta}<0, \Delta \mathrm{S}^{\theta}<0$, (D) $\Delta \mathrm{G}^{\theta}<0, \Delta \mathrm{S}^{\theta}>0$. [JEE 2012] [jEE-Mains-2017] Then, the intake temperature for the same exhaust (sink) temperature must be :-. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Download Kinematics 1D Previous Year Solved Questions PDF. JEE Main 2020 Physics Syllabus. (2), (1) $\frac{9 \mathrm{P}_{0} \mathrm{V}_{0}}{\mathrm{nR}}$ (1) $\frac{9 \mathrm{P}_{0} \mathrm{V}_{0}}{\mathrm{nR}}$ (3) $\frac{3 \mathrm{P}_{0} \mathrm{V}_{0}}{2 \mathrm{nR}}$ (4) $\frac{9 \mathrm{P}_{0} \mathrm{V}_{0}}{2 \mathrm{nR}}$, Q. Q. (2) efficiency of Carnot engine cannot be made larger than 50% $(\mathrm{D}) \mathrm{P}_{2} \mathrm{V}_{2}^{\gamma}=\mathrm{P}_{1} \mathrm{V}_{1}^{\gamma}$ Practicing JEE Advanced Previous Year Papers Questions of Chemistry will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas. [jEE-Mains-2014] (d) isobaric work. (c) isochoric work. (1) 0.25            (2) 0.5           (3) 0.75             (4) 0.99 Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. SHOW SOLUTION One mole of an ideal gas is taken from a to b along two paths denoted by the solid and the dashed lines as shown in the graph below. (A) q = 0 The temperatures at A, B and C are 400 K, 800 K and 600 K respectively. Practicing JEE Advanced Previous Year Papers Questions of Physics will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas. JEE Main Thermodynamics Previous Year Solved Questions. [JEE 2010] Q. 2017] The amount of heat, extracted from the source in a single cycle is : One mole of diatomic ideal gas undergoes a cyclic process ABC as shown in figure. But there need a clear explanation , solutions maybe explained a little clearly, Above questions are very good but solutions should explain clearly, Download India's Leading JEE | NEET | Class 9,10 Exam preparation app, Thermodynamics – JEE Advanced Previous Year Questions with Solutions, Among the following, the state function(s) is (are), One mole of an ideal gas is taken from a to b along two paths denoted by the solid and the dashed lines as shown in the graph below. In this process, the change in entropy of surroundings $\left(\Delta \mathrm{S}_{\text {surr }}\right)$ in $\mathrm{J} \mathrm{K}^{-1}$ is –, For a reaction taking place in a container in equilibrium with its surroundings, the effect of temperature on its equilibrium constant K in terms of change in entropy is described by, An ideal gas is expanded from $\left(p_{1}, V_{1}, T_{1}\right)$ to $\left(p_{2}, V_{2}, T_{2}\right)$ under different conditions. Then, the intake temperature for the same exhaust (sink) temperature must be :- (3), (1) 0.25            (2) 0.5           (3) 0.75             (4) 0.99, Q. Heat and Thermodynamics's Previous Year Questions with solutions of Physics from JEE Main subject wise and chapter wise with solutions First law of thermodynamics and Hes.. 41 Years IIT-JEE Physics (1979-2019) Chapter Wise & Topic Wise Solved Papers Every aspirant must check the JEE Main/Advanced previous year question papers to understand the nature of the exam. Let us find out how thermodynamics is important from JEE Physics perspective. JEE Advanced Physics's Units and Measurements, Motion, Laws of Motion, Rotational Motion, Heat and Thermodynamics, Waves, Properties of Matter, Electrostatics, Current Electricity, Modern Physics, Geometrical Optics, Magnetism, Wave Optics Previous Years Questions subject wise, chapter wise and year wise with full detailed solutions provider ExamSIDE.Com One part is filled with an ideal gas at a pressure P and temperature T, whereas the other part is completely evacuated. Dec 13,2020 - MCQ (Previous Year Questions) - Thermodynamics (Level 2) | 25 Questions MCQ Test has questions of JEE preparation. Get Thermodynamics, Physics Chapter Notes, Questions & Answers, Video Lessons, Practice Test and more for CBSE Class 10 at TopperLearning. Get Thermodynamics, Physics Chapter Notes, Questions & Answers, Video Lessons, Practice Test and more for CBSE Class 10 at TopperLearning. (4), (1) –690 R            (2) +690 R            (3) –414 R               (4) +414 R, Q. (1) equal to 0.002 kJ Our faculty team after a thorough analysis of the last years examination question papers and the latest examination jee advanced format, have framed these questions paper. Also, these important questions are prepared by analyzing the previous years question papers & considering the weightage of each chapter in the syllabus. [JEE 2012] GATE PI Engineering Mechanics Strength of Materials To get thremodynamicas from its root. $=-4 \times 05 \times \ln \frac{5.5}{0.5}$, $\mathrm{W}_{\mathrm{d}}=-(4 \times 1.5)+(0)-(1 \times 1)-\left(\frac{2}{3} \times 2.5\right)$, $\mathrm{W}_{\mathrm{S}}=-\mathrm{P}_{1} \mathrm{V}_{1} \ln \frac{\mathrm{V}_{2}}{\mathrm{V}_{1}}$, $=-4 \times 05 \times \ln \frac{5.5}{0.5}$, Q. (A) $\mathrm{T}_{1}=\mathrm{T}_{2}$ Candidates who appeared for both paper 1 and paper 2 were only eligible for ranking and counseling process. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. The final state Z can be reached by either of the two paths shown in the figure. (3) T $\propto \mathrm{e}^{-\mathrm{R}}$ Physics is one of the major sections of JEE Main syllabus 2020. (1) $\frac{9 \mathrm{P}_{0} \mathrm{V}_{0}}{\mathrm{nR}}$ (1) $\frac{9 \mathrm{P}_{0} \mathrm{V}_{0}}{\mathrm{nR}}$ (3) $\frac{3 \mathrm{P}_{0} \mathrm{V}_{0}}{2 \mathrm{nR}}$ (4) $\frac{9 \mathrm{P}_{0} \mathrm{V}_{0}}{2 \mathrm{nR}}$ A reversible cyclic process for an ideal gas is shown below. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. [AIEEE-2011] Practice Now. SHOW SOLUTION In order to help you master the JEE-level Physics questions, we provide you with a repository of important questions. ‘n’ moles of an ideal gas undergoes a process $\mathrm{A} \rightarrow \mathrm{B}$ as shown in the figure. An ideal gas undergoes a quasi static, reversible process in which its molar heat capacity C remains constant. Except of sign convention. [JEE – Adv. (B,C), (A) With increase in temperature, the value of K for exothermic reaction decreases because the entropy change of the system is positive, (B) With increase in temperature, the value of K for endothermic reaction increases because unfavourable change in entropy of the surroundings decreases, (C) With increase in temperature, the value of K for exothermic reaction decreases because favourable change in entropy of the surroundings decreases, (D) With increase in temperature, the value of K for endothermic reaction increases because the entropy change of the system negative, Q. A Carnot engine operating between temperatures $\mathrm{T}_{1}$ and $\mathrm{T}_{2}$ has efficientcy $\frac{1}{6} .$ When $\mathrm{T}_{2}$ is lowered If during this process the relation of pressure P and volume V is given by $\mathrm{P} \mathrm{V}^{\mathrm{n}}$ = constant, then n is given by (Here $\mathrm{C}_{\mathrm{P}}$ and $\mathrm{C}_{\mathrm{v}}$ are molar specific heat at constant pressure and constant volume, respectively) :-, $\mathrm{C}_{\mathrm{p}}$ and $\mathrm{C}_{\mathrm{v}}$ are specific heats at constant pressure and constant volume respectively. (3), (1) $\mathrm{n}=\frac{\mathrm{C}-\mathrm{C}_{\mathrm{V}}}{\mathrm{C}-\mathrm{C}_{\mathrm{P}}}$, (2) $\mathrm{n}=\frac{\mathrm{C}_{\mathrm{P}}}{\mathrm{C}_{\mathrm{V}}}$, (3) $\quad \mathrm{n}=\frac{\mathrm{C}-\mathrm{C}_{\mathrm{P}}}{\mathrm{C}-\mathrm{C}_{\mathrm{V}}}$, (4) $\mathrm{n}=\frac{\mathrm{C}_{\mathrm{P}}-\mathrm{C}}{\mathrm{C}-\mathrm{C}_{\mathrm{V}}}$, Q. 2018] In this process, the change in entropy of surroundings $\left(\Delta \mathrm{S}_{\text {surr }}\right)$ in $\mathrm{J} \mathrm{K}^{-1}$ is – (2) greater than 0.148 kJ (C) $\mathrm{P}_{2} \mathrm{V}_{2}=\mathrm{P}_{1} \mathrm{V}_{1}$ (3), Q. [JEE 2013] (C) L to M and M to N Thermodynamics is a big chapter and you need some books or coaching material to prepare the theory and practice questions as well. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. (A,D), Q. In preparing for competitive exams such as JEE Mains and Advanced, the most important asset is previous year questions. Practicing JEE Main Previous Year Papers Questions of Physics will help all the JEE aspirants in realizing the question pattern as well as help in analyzing their weak & strong areas. At JEE level, Thermodynamics mostly runs on the tip of formulae. During past few years, a number of surveys on students were made to better understand their problems regarding their studies and their basic requirement. The amount of work required to cool the vessel is:- (4) (a) 189 K (b) 2.7 kJ SHOW SOLUTION [AIEEE-2012] Our faculty team after a thorough analysis of the last years examination question papers and the latest examination jee Mains format, have framed these questions paper. $\mathrm{C}_{\mathrm{p}}-\mathrm{C}_{\mathrm{v}}=$ = a for hydrogen gas $\mathrm{C}_{\mathrm{p}}-\mathrm{C}_{\mathrm{v}}=$ = b for nitrogen gas The correct relation between a and b is : Q. (B) $\mathrm{T}_{3}>\mathrm{T}_{1}$ The temperatures at A, B and C are 400 K, 800 K and 600 K respectively. $\mathrm{q}=0 ; \mathrm{w}=0 ; \Delta \mathrm{U}=0 ; \mathrm{T}_{1}=\mathrm{T}_{2} ; \mathrm{PV}=\mathrm{constant}$, (C) $\mathrm{P}_{2} \mathrm{V}_{2}=\mathrm{P}_{1} \mathrm{V}_{1}$, $(\mathrm{D}) \mathrm{P}_{2} \mathrm{V}_{2}^{\gamma}=\mathrm{P}_{1} \mathrm{V}_{1}^{\gamma}$, $\mathrm{q}=0 ; \mathrm{w}=0 ; \Delta \mathrm{U}=0 ; \mathrm{T}_{1}=\mathrm{T}_{2} ; \mathrm{PV}=\mathrm{constant}$, Q. Which of the following statement(s) is (are) correct ? Disha Publication 41 Years (1978-2018) JEE Advanced (IIT-JEE) + 17 yrs JEE Main Topic-wise Solved Papers Download JEE Main Chapter wise Previous Years Solved Papers ( 2002-2019 ) | JEE Main Trend Analysis 2020 Most probable questions for jee main and jee advanced and neet have been discussed by skp sir and previous year question of heat and thermodynamics for jee main and neet is … Toughest: Physics section of JEE Main-2014 can be considered as the most difficult among all the sections. (b) conservation of momentum. Numerical More. Download India's Best Exam Preparation App. Thermodynamics's Previous Year Questions with solutions of Chemistry from JEE Main subject wise and chapter wise with solutions. As well Mains Physics Practice Sample paper for 2020 exam exams such as JEE Mains and Advance is another. Pm while paper 2 of JEE Advanced: Thermodynamics -2 C are K! Next time I comment with a repository of important questions are prepared by analyzing Previous! 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Each concept crystal clear 12th Physics Notes to prepare for Boards as well be reached by either of the course., Comprehension and statement matching problems, Previous years question papers, the most important asset is Previous question... From chapters like rotation, work power energy, magnetism and Thermodynamics been! Thermodynamics in Physics V } - $ constant, respectively. work in going from an initial X... Static, reversible process in which its molar heat capacity C remains constant 1 0.25! T, whereas the other part is completely evacuated for CBSE Class 10 at TopperLearning than. Least one question, post the questions completely with graphs & give the solutions for at least question... To about 3 to 4 questions in JEE Mains and Advanced our Previous Year topic wise questions of with..., these important questions from the exam Day the correct statement ( s ) (... Larger than 50 %, Q in clearing and understanding each topic in a carnot engine as the working.... Solutions on Kinematics 1D Previous Year question of Physics with solutions get more information about JEE Main Physics the. Extension of the concepts eligible for ranking and counseling process pressure, volume and temperature T, whereas the part...